Mundane Position in the Placidus System


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Mundane Position in the Placidus System

March 21, 2023, 8:56 a.m. Mark Rusborn 1 min. to read


As described in the article on the Placidus system, the mundane position is the intersection of the dividing S-shaped curve passing through the planet with the celestial equator.

Knowing the mundane position is extremely important for calculating primary directions. Two planets are considered spatially conjunct on the celestial sphere when their mundane positions coincide.

In this article, we will derive equations for calculating the mundane position in the Placidus system. We have the coordinates of the planet, the observer's latitude, and the local sidereal time (or RAMC) as initial data.

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What does the mundane position look like in the Placidus system?

According to the definition, the mundane position has the same deviation from the prime meridian on the equator as the planet $P$ on its diurnal/nocturnal semi-arc.

Mundane position
Fig. 1 - Mundane position.

The ratio $R$ of meridian distance to semi-arc is the same for both points

$$ R = \frac{MD_P}{SA_P} = \frac{MD_M}{90°} $$

Here $MD_P$ and $MD_M$ are the upper or lower meridian distance of planet $P$ and its mundane position $M$, and $SA_P$ is its diurnal/nocturnal semi-arc.

Mandane Position Equation

We take the upper meridian distance and diurnal semi-arc for the planet above the horizon and the lower meridian distance and nocturnal semi-arc for the planet below the horizon.

If we substitute eq. (1-3) from the article on RAMC, we can rewrite the same equation in the following form:

$$ R = \frac{|RA_P - RA_{MC/IC}|}{|90° \pm AD_P|} = \frac{|RA_M - RA_{MC/IC}|}{90°}\tag{1} $$

Here $AD_P$ is the ascension difference of the point $P$ described by equation (2) of ascension difference.

Finally, the equation for the mundane positions of the planet with equatorial coordinates $(RA, D)$ is following:

$$\begin{cases} RA_M = RA_{MC/IC} \pm 90° \times R \\\ R = |RA_P - RA_{MC/IC}| / |90° \pm AD_P| \\\ AD_P = \arcsin(\tan\phi \tan D) \end{cases}\tag{2}$$

where the $\phi$ is the observer's geographical latitude. The converse equation is following:

$$\begin{cases} RA_P = RA_{MC/IC} \pm |90° \pm AD_p| \times R \\\ R = |RA_M - RA_{MC/IC}| / 90° \\\ AD_P = \arcsin(\tan\phi \tan D) \end{cases}\tag{3}$$

Mark Rusborn

Mark Rusborn

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